Sum of Digits present in number

import java.io.*;

public class SumOfDigits
{
  public static void main(String[] args) throws IOException
  {
     BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
     System.out.print("\nEnter Number::");
     int n = Integer.parseInt(br.readLine());
     int t = n;
     int r;

     for (r = 0; n > 0; n = n / 10)
        r = r + n % 10;

     System.out.println("\nSum of Digits of " + t + " is :: " + r);
  }
}

OUTPUT::

Enter Number::12345


Sum of Digits of 12345 is :: 15

Using Recursive Function

import java.io.*;

public class SumOfDigitsRecursive
{
  int sum(int n)
  {
     int res;
     if (n < 0)
        n *= -1;  // making number positive

     if (n == 0)
        return 0;
     else
     {
        res = n % 10 + sum(n / 10);
        return res;
     }
  }

  public static void main(String[] args) throws IOException
  {
     BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
     System.out.print("Enter Number:: ");
     int n = Integer.parseInt(br.readLine());

     SumOfDigitsRecursive obj = new SumOfDigitsRecursive();
     int s = obj.sum(n);

     // Displaying Result
     System.out.println("\nSum of Digits is:: " + s);
  }
}

OUTPUT::

Enter Number:: 12345

Sum of Digits is:: 15

-----

Firoz Memon

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          C++ Codes 4 Beginners

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